Espaces probabilisés 1 Définition 2 Propriétés élémentaires des

Ω = {0,1}0 1
Ω =
Ω = R+
Ω = {1,2,3,4,5,6}
σ
(An)nSS
n
AnS
A S A S
SP(Ω) S
S
∅ ∈ S
(An)nT
n
AnS
P(Ω) Ω
R R B(R)
SPS
[0,1]
P(Ω) = 1
(An)nS AiAj=
i6=j
P([
n
An) = X
n
P(An).
(Ω, S, P)
A B A, B S
P(A)=1P(A)
P()=0
P(B) = P(AB) + P(AB)
P(AB) = P(A) + P(B)P(AB)
A A
P(A) + P(A) = P(AA) = P(Ω) = 1.
A= Ω
P(Ω) + P(Ω) = 1 = P()+1.
BA B A B =BΩ = B(AA)=(BA)(BA)
P(B) = P((BA)(BA)) = P(BA) + P(BA).
A B A
P(AB) = P(A(BA)) = P(A) + P(BA).
P(BA) = P(B)P(AB)
P(AB) = P(A) + P(B)P(AB).
(Ai)1inn
P n
[
i=1
Ai!=
n
X
i=1
P(Ai)X
1i<jn
P(AiAj) + X
1i<j<kn
P(AiAjAk) + ··· + (1)nP n
\
i=1
Ai!
P
P(Ω) Ω
P({ω})ωA
P(A) = X
ωA
P(ω).
1 = P(Ω) = PωP(ω)
1={pile, f ace}1
P P(pile) = P(f ace)=1/2
k k 2 Ωk= Ωk
1k
(Ωk)=2kkP(ω)=2kωk
P(ω) = p ω p= 1/(Ω)
P(A) = X
ωA
P(ω) = X
ωA
1
(Ω) =(A)
(Ω) ,
P(A)
N
N
P(1) = 1/6
P(2) = P( ) = 5
36
k2
P(k) = P(k1 ) = 5
6k11
6.
NPk1P(k) = 1
f:RR{x, f(x)
y}∈B(R)yR R
AR
P(A) = ZA
f(x)dx.
[a, b]a<b
P(A) = ZA[a,b]
1
badx.
R
f(x) = 1
2πσ exp (xm)2
2σ2
mRσR+
A B
AB A P(AB)=1/6
P(B) = 5/6
B
P(AB)/P(B)
A B P(B)6= 0 A
B B P(A/B)
P(A/B) = P(AB)
P(B).
BP(B)Q(A) = P(A/B)
S
Q
AS
0Q(A) = P(A/B)1
P(B) = P(AB) + P(AB)P(AB)
Q(Ω) = P(Ω/B) = P(Ω B)
P(B)=P(B)
P(B)= 1.
(An)n
Q(S
n
An) = P((S
n
An)/B) =
P((S
n
An)B)
P(B)=
P(S
n
(AnB))
P(B)=X
n
P(AnB)
P(B)=X
n
P(An/B)
QS
(Ai)iIP(Ai)>0
i
[
iI
Ai= Ω et AiAj=,i6=j.
(Ai)iIB
P(B) = X
iI
P(BAi).
(Ai)iIS
iI
Ai= Ω
P(B) = P(BΩ) = P(B(S
iI
Ai)) = P(S
iI
(BAi))
AiBAi
P(B) = X
iI
P(BAi).
(Ai)iIBP(B)6= 0
P(Ai)6= 0 iI
P(B) = X
iI
P(B/Ai)P(Ai).
P(Ak/B) = P(Ak)P(B/Ak)
P
iI
P(Ai)P(B/Ai)kI.
A B P(B)6= 0 0 <P(A)<1
P(A/B) = P(B/A)P(A)
P(A)P(B/A) + P(A)P(B/A).
P(B) = X
iI
P(BAi).
P(B/Ai) = P(BAi)
P(Ai)
P(B) = X
iI
P(B/Ai)P(Ai).
P(Ak/B) = P(AkB)
P(B)
P(Ak/B) = P(B/Ak)P(Ak)
P(B).
P(B)
P(Ak/B) = P(Ak)P(B/Ak)
P
iI
P(Ai)P(B/Ai).
1N A
B
A B
A B
A B
P(A/B) = P(A)
P(B/A) = P(B)
P(AB) = P(A)P(B).
P(A/B) = P(A)P(AB)
P(B)=P(A)
P(AB) = P(A)P(B)
P(BA)
P(A)=P(B)
P(B/A) = P(B)
A B A `B
P(AB) = P(A)P(B).
A B
A`AP(A) = 0 ou P(A) = 1
A`BA`BA`BA`B
A`AP(AA) = P2(A)P(A)(1 P(A)) = 0 P(A) = 0 P(A)=1
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