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3/5 2/3
p p
A B A Bc
AcBc
X Y
n∈ {0,1,...,5}Y
n
X Y Z
X
X
X Y
P(X)=2/5,P(Y) = 3/5.
X Y
X Y X

n≥3j k
Ω := {a, b, c, d} F := P(Ω) PF
P({a}) = αP({b}) = βP({c}) = γP({d}) = δ6= 0 α, β, γ, δ
A:= {b, c}B:= {c, a}C:= {a, b}
A B B C
p
A B A C
6−A C p
b n
`
p
P( ) = p Xkk
Xkn∈N∗
P(∃k∈N∗, Xk=n)
λ
n pj
j1≤j≤r r > 1Njj
N:= (N1, . . . , Nr)
NjNjNkj Nj= 0