semaine 20 - Pierre

u:I→Rαuαuα+1
α+ 1
f[0 ; 1]
f≥0⇐⇒ Z1
0
f(t) dt≥0
2x2x+1
x+ 1
Z1
0
√et−1 dt= 0
fRG(x) = Z2x
x
f(t) dt G0(x) =
f(2x)−f(x)
A(x)
f A0(x) = f(x)
f F F 0=f
F1F2f
k∈RF2=F1+k
x0y0f
F(x0) = y0

Zb
a
f(t) dt=F(b)−F(a)F f
a a 0 0
−
f≥0
f≥0
m≤f≤M=⇒m(b−a)≤Zb
a
f(x) dx≤M(b−a)
I1I2I3I5I6I7I10 I11 I12 I13
A E K
B C D F G
anbn