ABC A cos(d
ABC)
d
ABC
cos(d
ABC) = cˆot´e adjacent
hypot´enuse =AB
BC .
cˆot´e adjacent
hypot´
enuse
A B
C
−1≤cos(d
ABC)≤1
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£
¡
¢
COS
(30 ) 0,866 10−3
¨
§
¥
¦
COS−1
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¡
¢
ACS
cos(d
ABC) = 3
5d
ABC 53
ABC A
sin(d
ABC)d
ABC
sin(d
ABC) = cˆot´e oppos´e
hypot´enuse =AC
BC .
cˆot´e oppos´e
hypot´
enuse
A B
C
−1≤sin(d
ABC)≤1
tan(d
ABC)d
ABC
tan(d
ABC) = cˆot´e oppos´e
cˆot´e adjacent =AC
AB .
cˆot´e oppos´e
cˆot´e adjacent
A B
C
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¡
¢
SIN ¤
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¡
¢
T AN
sin(30) = 0,5tan(30) = 0,577 10−3
¨
§
¥
¦
SIN −1¤
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¡
¢
ASN
sin(d
ABC) = 2
5d
ABC = 24
¨
§
¥
¦
T AN −1¤
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¡
¢
AT N
tan(d
ABC) = 1
2d
ABC = 27
(cosx)2+(sinx)2= 1
µAB
BC 2
+µAC
BC 2
= 1
d
ABC d
ABC
d
ABC x
(cosx)2+ (sinx)2= 1 cos2x+sin2x= 1
tanx =sinx
cosx
cos(d
ABC), sin(d
ABC)et tan(d
ABC)ABC
sin(d
ABC)
cos(d
ABC)
d
ABC x
tanx =sinx
cosx
cos sin tan
cos−1sin−1tan−1
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