MULTIPLES ET DIVISEURS

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{1,2,3,4,6,8,9,12,18,24,36,72}
{1,3,5,15,25,75}
{1,83}
{1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120}
{1,2,4,5,8,10,20,25,40,50,100,200}
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{ ± 1,±2,±5,±10,±25,±50}
−56 { ± 1,±2,±4,±7,±8,±14,±28,±56}
−8{ ± 1,±2,±4,±8}
{ ± 1,±3,±7,±9,±21,±63}
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−500 −17 ×29 = −493 −16 ×29
17 ×29 = 493
−17
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(2k+ 1) + (2k+ 3) = 4(k+ 1)
n+ (n+ 1) + (n+ 2) = 3(n+ 1)
n+ (n+ 1) + (n+2)+(n+3)+(n+ 4) = 5(n+ 2)
n+ (n+ 1) + (n+2)+(n+ 3) = 4n+ 6
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n−4 = 5k n2−1 = (5k+ 4)2−1 = 5(5k2+ 8k+ 3)
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n−2 = 7k n3−1 = (7k+ 2)3−1 = 7(49k3+ 42k2+ 12k+ 1)
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7a+ 5b=nd 4a+ 3b=md
3(7a+5b)−5(4a+3b) = a=d(3n−5m)−4(7a+5b)+7(4a+3b) =
b=d(−4n+ 7m)
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a b a ≥b)
a+b+ab +a−b+a
b= 2a+ab +a b= 243
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b= 243 −2a−ab

a
b(b+ 1)2= 243 243 = 35(b+ 1)2
(a;b) = (54 ; 2) (a;b) = (24 ; 8)
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x−3 (x−3)(x+ 3) + 12 x−3 (x−3)(x+ 3) + 12 x−3
x−3x−3 (x−3)(x+ 3) + 12 = x2+ 3
{0,1,2,4,5,6,7,9,15}
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x−2x+ 5 = (x−2) + 7 x−2x−2x−2
x−2−7−1
x−2x−2 (x−2) + 7 = x+ 5
x−2−7−1S={ − 5,1,3,9}
x+ 7 2x+ 15 = 2(x+ 7) + 1 S={ − 8,−6}
x−1x2= (x−1)(x+1)+1 S={0,2}
x+ 1 x3+ 2 = (x+ 1)(x2−x+1)+1 S={ − 2,0}