FF
αRxR
+
xαeαln(x)α
R
+x7→ xα
R
+xR
+,d
dx xα=αxα1.
α, β Rx, y R?
+
1/xα=xα
xαyα= (xy)α
xαxβ=xα+β
(xα)β=xαβ
ln(xα) = αln x
α
lim
x+xα= +.
0α= 0
eαln(x)
x y
xy 1
2(x2+y2).
p q 1
p+1
q= 1
p > 1
(x, y)(R+)2xy 1
pxp+1
qyq.
p q 1
p+1
q= 1
x1, ... , xn, y1, ... , ynn
t1, ... , tn|t1+... +tn| ≤
|t1|+... +|tn|
|x1y1+... +xnyn| ≤ |x1|p+... +|xn|p
p+|y1|q+... +|yn|q
q.
λR
+,|x1y1+... +xnyn| ≤ λp|x1|p+... +|xn|p
p+1
λq
|y1|q+... +|yn|q
q.
λ
|x1y1+. . . +xnyn| ≤ (|x1|p+... +|xn|p)1
p(|y1|q+...|yn|q)1
q.
x1, ..., xn, y1, ... , ynnNp]1,+[
k[[1, n]]
|xk+yk|p≤ |xk||xk+yk|p1+|yk||xk+yk|p1.
BY:
$
\
C
n
X
k=1
|xk||xk+yk|p1 n
X
k=1
|xk|p!1
p n
X
k=1
|xk+yk|p!11
p
n
X
k=1
|yk||xk+yk|p1 n
X
k=1
|yk|p+!1
p n
X
k=1
|xk+yk|p!11
p
.
(|x1+y1|p+... +|xn+yn|p)1
p(|x1|p+... +|xn|p)1
p+ (|y1|p+... +|yn|p)1
p.
p]1,+[nNx1, x2, ..., xnR
k(x1, ..., xn)kp= (|x1|p+... +|xn|p)1
p
k(x1, ..., xn)k|x1|,|x2|, ..., |xn|
p]1,+[,k(x1, ..., xn)k≤ k(x1, ..., xn)kpn1
pk(x1, ..., xn)k.
lim
p+k(x1, ..., xn)kp.
(p, q)(R
+)21/p + 1/q = 1 (a, b)R2a<b
f g [a;b]
λR
+,Zb
a
|fg| ≤ λp
pZb
a
|f|p+λq
qZb
a
|g|q.
Zb
a
|f|p= 0 Zb
a
|g|q= 0 Zb
a
|fg|= 0
λ
Zb
a
|fg| ≤ Zb
a
|f|p
1
pZb
a
|g|q
1
q
.
Zb
a
|f||f+g|p1Zb
a
|f|p
1
pZb
a
|f+g|p11
p
BY:
$
\
C
Zb
a
|g||f+g|p1Zb
a
|g|p
1
pZb
a
|f+g|p11
p
.
Zb
a
|f+g|p
1
p
Zb
a
|f|p
1
p
+Zb
a
|g|p
1
p
.
BY:
$
\
C
(xy)20
y x 7→ 1
pxp+1
qyqxy R+
xiλxiyi1
λyi
λp(|x1|p+... +|xn|p) = 1
λq(|y1|q+... +|yn|q)
|xk+yk|p=|xk+yk|p1|xk+yk|.
q=p
p1
|x1|, ... , |xn| |x1+y1|p1, ... , |xn+yn|p1
|xi| k(x1, ..., xn)k
(λf, 1
λg)
λ+0+
λ λpRb
a|f|p=λqRb
a|g|q
BY:
$
\
C
1 / 9 100%
La catégorie de ce document est-elle correcte?
Merci pour votre participation!

Faire une suggestion

Avez-vous trouvé des erreurs dans linterface ou les textes ? Ou savez-vous comment améliorer linterface utilisateur de StudyLib ? Nhésitez pas à envoyer vos suggestions. Cest très important pour nous !