TDproba19

A B P (A∩B) = 1
4P(¯
A) = 1
3P(B) = 1 2
P(A∪B)
A1A2A175%
A250% A1
A2A1A2
A1
36% 22%
30%
X
xi
P[X=xi]
P[X > 0]
X

A1=
1
2
A2=
(Ω1,P1)
A1P1(A1)
(Ω2,P2)
A2P2(A2)
P1(A1)P2(A2)
X
P([X < 3]) = 1/3; P([X > 3]) = 1/2; P([X= 1]) = P([X= 2]).
X
X
C3
5
E(X)
10−6
X
W∈R
W