I Informatique II Trigonométrie III Étude d`une fonction IV Résolution

n
Pn
k=0 k5
n
σ(n) = n σ(n)
n n
n
n
n
1n
x√3 sin(5x) = cos(12x)−cos(2x)
f
f(x) = ln ex+e−x
2
f
f
g f R+gR+R+g−1
f g−12 ln 2 ≈0,693
C
(E)z3+pz +q= 0
p q p 6= 0

z0(E)
∃(u, v)∈C2,(u+v=z0
uv =−p
3
u v
u3v3
(∗)Z2+qZ −p3
27 = 0
(E)
(∗)Z2+qZ −p3
27 = 0
U V
UV U 6= 0 V6= 0
u3=U u1, u2, u3u2, u3
u1j= exp 2iπ
3
v1u1v1=−p
3
v3
1=V
v3=V v1
z1=u1+v1
z2=u1j2+v1j
z3=u1j+v1j2
z1, z2, z3(E)
z0(E)z0z1, z2z3
z3−3z+ 1 = 0
cos