Correction

2 3−◦1
√2
22,32,42,52,62,72
22= 4,32= 9,42= 16,52= 25,62= 36,72= 49
n n = 2k
k∈Zn= 2k+ 1
k∈Z
a) 99 −110
99 = 2×49+1 k= 49 −110 = 2×(−55) k=−55
b)n= 2k n2
k0k n2= 2k0
n2
n
n= 2k k ∈Z
n2= (2k)2= 4k2= 2 ×(2k2)k0= 2k2
n2= 2k0n2
c)n= 2k+ 1
n2
n= 2k+ 1
n2= (2k+ 1)2= 4k2+ 4k+ 1 = 2 ×(2k2+ 4k)+1
k0= 2k2+ 2k n2= 2k0+ 1
n2
a)
b)

◦
n2n n
n n2
a)
b)
√2
√26∈ Q
√2 = a
b
a b 2
√2 = a
b
2 = √22 =a
b2
=a2
b2.
a2a
a2= 2b2
a2a
a= 2q q ∈Z
a2= 4k k b2
b
a2= (2q)2= 4q2= 4k k = 2q
2b2=a2= 4k b2= 2k b2
b
a
b
a b a/b
√2∈Q√26∈ Q