Corrigé

X
(Pθ)θ∈I
θ
θ n (X1, ..., Xn)
X
Tn=f(X1, ..., Xn)θ Tn
θ
p B
Tn=
n
P
i=1
Xi
n
n
xi
t20 =
8
20
=
2
5

X
(Xn)
Xn+1 Xn
Xn=i Xn+1 {i−1; i+ 1}
n+∞
0,27
θ

e−θ
U100 e−θ
T100 T100 e−θU100
T100
T100 U100 T100
U100
20
X X 20
1/4
X=i Y 20 −i
20 −i1/4

θ0,435
Tn
θ n (Tn)n
+∞
(Tn)

(Tn) 7/16 θ= 7/16
X →B(p)p
(X1, ..., Xn)n X
[Xn−1
√n;Xn+1 √n]p95%
p p
Xnp∈[Xn−1
√n;Xn+1 √n]
p
p= 0.2n= 1000
p∈[Xn−1
√n;Xn+1 √n]
P(p∈[Xn−1
√n;Xn+1 √n]) '0,97
P(p∈[Xn−1
√n;Xn+1 √n]) ≥0,95
95%