Introduction à la mécanique des uides Notes de cours

µ
•µ=P.M
R.T = 1,3 kg ·m−3M= 29 g ·mol−3
P= 1 atm T= 273,15 K
•µ= 103kg ·m−3
n
•n=P
kB.T = 2,7.1025 m−3P= 1 atm T= 273,15 K
•n=µ
NA.M = 3,3.1028 m−3M= 18 g ·mol−3
χT=−1
V∂V ∂P T
= + 1
µ∂µ ∂P T
P T V µ
χT= 4,4.10−10P a−120◦C
∆µ
µ= 4%
◦

•1nm = 10−9m
•1mm
10km
•
N1g
d3τ
VΣ Σ
V
Gouvert =ZZZV g.d3m=ZZZV µ.g.d3τ
g Gouvert
µ
G J g J·kg−1
•tΣA
•t+dt ΣB
G
G
DG
Dt =Gf(t+dt)−Gf(t) dt =dG dt +δms dt gs−δme dt ge
•DG
Dt G
•dG
dt =∂ ∂t RRRVg.d3mG
•δme
dt geδms dt gsG
G
G
◦

◦

S
Dm=ZZS µ.−→ v .−−→ d2S
kg3·s−1δm dt Dm=δm
dt
S
Dv=ZZS
−→
v .−−→ d2S
m3·s−1
M
DM
Dt =dM dt +δmB dt −δmA dt = 0
•MDM
Dt = 0
•MdM
dt =∂ ∂t RRRVµ.d3τ
•δmA
dt
δmB
dt
δme
dt =δms dt =Dm
δVe
dt =δVs dt =DV
δme
dt =δms dt =Dm
Dm
M T
BP
◦

V
~
P=ZZZV ~v.d3m=ZZZV µ~v.d3τ
D~ P
Dt =~
Pf(t+dt)−~ Pf(t)
dt =d~
P
dt +δms dt ~vs−δme dt ~ve
d~ P
dt δms
δmedt ~vs~ve
D~ P
Dt = Σ ~
Fext
Σ~ Fext
VΣ
d2Σ−−→ d2F
P
Dm
◦