Devoir maison de thermodynamique

TI= 485K pI= 20 xVI = 1
T0
xL= 1 xV= 1
p vL(m3.kg−1)hL(kJ.kg−1)sL(kJ.kg−1.K−1)vVhVsV
−3
−3
I→F
TFTc
•→
TF
T→
→2
qF

•→
T3Tc
wu
•
T
→
qC
•→
wuq
qFwuqChii∈[1; 4]
TF=−18◦C
Tc= 20◦C
T = −30◦C
T2−T′
2= 10◦C
Tcd = 40◦C
T4−T′
4=−10◦C
ln P, h
•P
•P
•P/P
•x1
•T3
•qF
•qc
•wu
•e
•ec

◦x= 0,2
ln P, h
−3m3.kg−1