3ème E DS1 calcul littéral 2015 – 2016 Sujet 2
CORRECTION
5
Exercice 1: (6 pts)
Développer et réduire les expressions suivantes :
A = (7x + 5)²
B = (x - 5)(9 – 3x)
C = (2x − 3)²
D = (5x + 2)(5x – 2)
E = (x - 1)² + 7x(2 + x)
F = (x - 3)(2x + 1) – 3x(5x + 2)
A = (7x)² + 2×7x×5 + 5² = 49x² + 70x + 25
B = 9x – 3x² - 45 + 15x = -3x² + 24x – 45
C = (2x)² - 2×2x×3 + 3² = 4x² - 12x + 9
D = (5x)² - 2² = 25x² - 4
E = x² - 2x + 1 + 14x + 7x² = 8x² + 12x + 1
F = 2x² + x – 6x – 3 – 15x² - 6x = -13x² - 11x - 3
Exercice 2: (6 pts)
Factoriser, si possible, les expressions suivantes :
A = 3a(a - 2) + 3a(1 + a)
B = x² + 10x + 25
C = 4x² - 20x + 25
D = 16 – 9y²
E = 49 - (3x + 1)²
F = (x + 3)(x – 9) – (x + 3)²
A = 3a[(a – 2) + (1 + a)] = 3a(2a – 1)
B = x² + 2×x×5 + 5² = (x + 5)²
C = (2x)² - 2×2x×5 + 5² = (2x – 5)²
D = 4² - (3y)² = (4 – 3y)(4 + 3y)
E = 7² - (3x + 1)² = [7 + (3x + 1)][7 – (3x + 1)] = (3x + 8)(-3x + 6) = -3(3x + 8)(x –
2)
F = (x + 3)[(x - 9) – (x + 3)] = -12(x + 3)
Exercice 3: (3 pts)
Le triangle ABC est-il rectangle en C quelle que soit la valeur de x ?
Justifier la réponse.
AB² = (13x + 4)² = (13x)² + 2×13x×4 + 4² = 169x² + 104x + 16
BC² + AB² = (5x + 3)² + (12x + 5)² = (5x)² + 2×5x×3 + 3² + (12x)² + 2×12x×5 +
5²
BC² + AB² = 25x² + 30x + 9 + 144x² + 120x + 25 = 169x² + 150x + 34