Contrôle n 1

◦
ρ
L
v
η−1−1
η ν
2−1
ν
η
p=h
λh= 6.62 10−34 λ= 780
−→
v0
v0=−1mRb = 142.10−27
h
vrec
Γ/2 Γ = 6
g
Ts
> Ts

kBT
kB
T=αf(v)α
α=√.
vrec
kB= 1.38 10−23
−→
v0
a
A
C
a
a
B
q0
D
v0
|−→ N(θ)|θ t
θ0|−→ N|θ0B
vB
dAB
a= 130 m= 800 g= 9.8−2
v0= 126 −1θ0vBdAB