Correction - Normalesup.org

1,2,3,4,5,6
Ω
1
6
3A
A p(A) = A
Ω=3 6=1 2
A∩B={3}1A∩B
p(A) = A∩B
Ω=1 6
A∪B p(A) = 5
6
B
A∩B
A∪B
A p(A) = 135
450 = 0,3
B p(B) = 198
450 = 0,44
A∩B p(A∩B) = 54
450 = 0,12
A∪B p(A∪B) = p(A) + p(B)−p(A∩B) = 0,62
54
135 = 0,4

7,29
100 ∗2194 '160
x6,14
100 ∗x= 160
x= 160 ∗100
6,14 '2605
A p(A) = 17376
36673 = 0,474
D p(D) = 5026
36673 = 0,137
A36673 −
17376 = 19297 p(A) = 19297
36673 '0,526
A∩D
5026 −1921 = 3105
p(A∩D) = 3105
36673 '0,085
A∪D p(A∪D) = p(A) + p(D)−p(A∩D) = 0,579
2092
4302 '0,486