TD OH1 et OH2 - ENT Moodle du Lycée du Hainaut

m
k
x
x0xeq m
→
Fk x0x→
ux
xeq x0g m k
m
xeq
x
x xeq m k ω0T0
t= 0 m
xeq m v0
→
v(0) = v0
→
uxx(t)
x(t)
t= 0
i
t= 0+
i(t)
i(t)
• •

k= 2,105 N/m
l0= 20 cm
m
z
g
α
g= 9,81 m.s−1m= 75 kg ∆m= 100 kg α = 4,9N.m−1.s
∆m
→
FA=−∆m
→
g
z
˙z∞
˙z(t) ˙z∞α
m
→
FA=−∆m(1 −z
z0
)
→
g
z∈0,z0
2z0= 10 km
z
τ ω0ze
z+z
τ+ω2
0(z−ze)=0
T
• •

θ
dθ
dt θ
θ(t)
˙
θ= 0 θ0π/2
θ0
M
Ox
k
l0
leq
O O
x
x0x06= 0
x
x(t)
• •

T0k m
ω2
0=2k
m
x(t)
Ep(t)
Ec(t)
E(t)k x0ω0t l0lq
• •

e(t) = E0cos(ωt)
i(t)
e(t)
i(t)
e(t)e(t)
e(t)
i(t)e(t)ω
I i(t)
I E0ω
ω0Q
I=E0/R
1 + j(ω
ω0−ω0 ω)
I i(t)E0R Q ω0
ω
I e(t)
I ω
I ω
i(t)ω= 100 krad/s ω = 200 krad/s
I
• •