COURS ET TD TORSION

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L
A
T
ORSION
S
IMPLE
C
OURS
G
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M
ECANIQUE
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LEXIO N
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LaboratoireMécaniquedeKORBA http://mimfs.jimdo.com/ Proposépar M
r
BenAbdallahMarouan
IMISEENSITUATION:
Ondonneledessind’ensemblepartielcidessousàl’échelle1:3delaboitedesvitessesd’untour(L180).
NB:
Ennégligeantlesforcesnormalesàl’axe,l’arbre(1)estmodélisécommesuit
:
Fig.1
S0
MA
Lignemoyenne S
MB
II.1Déduireletypedelasollicitationàlaquelleestsoumisl’arbre(1):..................................;
IIDEFORMATIONANGULAIREDUEALATORSION:
II.1
 Expérience
:
Placeruneéprouvetteàtraverslesélémentsdefixationetlabloquéedanslaportéfixe.
Fixerl’autreboutauleviermontédansdesroulementsàbilles(àla
longueurdésirée).
Réglerledispositifdemesuredetellesortequelepalpeurdu
comparateurestexactementenfacedel’entailledulevier.
Baisserlecomparateuretréglerl’aiguilleàzéro.
Remar que:
1tourdel’aiguilledecomparateurcorrespondà1°.
Pourunechargedonnée(
10N
);Compléterletableaucidessous:
l
(enmm)
a
(endegr é)
600 ..........
500 ..........
400 ..........
II.2Constatation:
Sousl’actiondelatorsion,lesfibresd’uncylindre,parallèleàsonaxegéométrique,s’enroulentsuivantdeshélicesautourdecet
axe.Seulelafibreaxialerestedroite
:
c’estlafibreneutre
.
5
30
21
35
8
41 2 3 6 34
10
9
23
64 7
32
L
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CIENCES
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r
BenAbdallahMarouan
Z
Y
Répartitiondescontraintes
G
tMaxi
M
tMaxi
r
II.3Etudedescontraintes:
Considér onsletr onçon(2)delapoutr er epr ésentéecicontre;
l’équilibr edesetr onçonimpliqueq ueleseffor tsdecohésions
déduisentunmomentM
tx
.
AupointM,l’effor télémen tair edf,r elatifàl’élémen tdesur facedSest
dansleplandelasection(S)etper pendiculair eaur ayonGM=ρ:(r ho).
Ler appor t:
(Taux)estlacontr aintetangentielaupointM.
II.4Relationcontr aintedéfor mation:
Ondémontr equelacontr aintedetor sionenunpointMdunesectionestper pendiculair e
àladistanceρdupointmàl’axedecylindr eetdelangleunitair edetor sionθ.
Gétantlemoduledélasticitétr ansversal.
Lacontr ainte
t
estmaximalepourρ=r .
Diagr a mmeder épar titiondescontr aintes
dansunesectiondr oite.
Lépr ouvetteestuncylindr edaxexx,desectionconstanteS.
SoientS
0
etSdeuxsectionsdr oitesdistantesde
l
et[m
0
m]une
génér atr ice.Sous
l’actiondescouples(F,F)(F
1
,F
1
)desenscontr air esSatour né
dunangle
a
par r appor tàS
0
pr isecommer éfér ence.
Lexpér iencemontr equepour unmomentetunesectiondonnés
:
=
l
a
=
1
1
l
a
=
q
en[rd/mm]:Angleunitairedetorsion
a
en(r d)(angleder otationentr edeuxsections)
df
M
z
(2)
G0
G0
x
y
Mt
G1
(1)
SectiondroiteS
1/2
x
1/2
M
z
df
ds
r
G
y
q t Grmax
=(3)
rq t G
=(2)
x'x
F'
1
O0
F'
O
a
O1
S1
F
S0
m0
1
l
a1
d
m m1
S
l1
F
Fig1
τ
dS
df
= (1)
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A
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ORSION
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ECHNIQUES
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OURS
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ECANIQUE
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r
BenAbdallahMarouan
II.5Relationcontraintemomentdetorsion:
(
I
0
/v
)estlemoduledetor sion delasectionconsidér éeen(m m
3
)
Danslhypothèsedunedéfor mationélastique,lemomentducoupledetor sionestdonnépar lar elation:
Enutilisantlesr elations(2)et(4)l’expr essiondelacontr aintede
glissementenunpointdunesectiondr oitesituéeàunedistance
r
dela
fibr eneutr eapour expr ession:
Cettecontr ainteestmaximalepour unpointdelafibr elapluséloignéedelafibr eneutr e;soitendésignant
r
Maipar
v
sadistanceàcetaxe:
II.6La conditionder ésistanceàlator sion:
Pour qu’uncylindr er ésisteentoutesécur itéàuncoupledetor siondonné,ilfautquelar elationsuivantesoitvér ifiée:
t
max
£
R
pg
avec
R
pg
:larésistancepr atiqueauglissementen(N/mm²)
Avec
Rpg= s
gRe
Rpg:r ésistancepr atiqueauglissement........en[MPa]
Reg:lim iteappar entedélasticitéauglissementen[MPa ]
s
:coefficientdesécur ité................[sansunité]
II.7Momentquadratiquepolaire:
Ä
V
ALEUR
D
U
M
OMENT
Q
UADRATIQUE
P
OLAIRE
D
E
S
URFACES
É
LEMENTAIRES
S
URFACES
I
O
V
v
Io
32
. 4
d p
2
d
16
. 3
d p
32
).( 44
dD
-
p
2
D
D
dD
.16
).( 44 -
p
Aretenir:
q
=
L
a
t
Maxi
=G.
q
.rMt=G.
q
.Io
t
Maxi
=
v
Io
Mt
avecv=rConditionder ésistance
t
Maxi
£
Rpg
Conditionder igidité
q £ q
lim
avec
q
=
IoG
Mt
.
Avec:
M
t
:
lemomentd ucoupledetor sionen(N.mm).
G
:lemoduledélasticitétr ansversaleen(N/mm²).
I
0
:lemomen tquadr atiquepolair ed’unesectiondr oiteen(mm
4
).
Mt=GθIo
(4)
v
MtMt
vτmaxI
I0
0
= =
Avec:Mten(N.mm),I
0
en(mm
4
)et
r
en(mm)
(5)
I
Mt
0
r t
=
L
A
T
ORSION
S
IMPLE
4
E
S
CIENCES
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ECHNIQUES
C
OURS
G
ENIE
M
ECANIQUE
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LEXIO N
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LANE
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IMPLE
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r
BenAbdallahMarouan
IIIA
PPLICATION
:
III.1Agitateur pour peintur e
Unetiged’agitateurpourpeintureestmontéeenboutdemandrinsuruneperceusedebricolage.Lalongueurdelatigeestde
700mm
.Lapuissancetransmiseestde
500watts
à
1500tr /mn
.Larésistancepratiqueauglissementdumatériaudelatigeestde
R
pg
=5daN/mm².
1
Déterminerlediamètreminimaldelatige.
d
min
:
..........................................................................................................
..........................................................................................................
..........................................................................................................
..........................................................................................................
..........................................................................................................
2
Calculerl’
angledetor sion
entrelesdeuxextrémitésdelatige(
G=8000daN/mm²
):
a
..........................................................................................................
..........................................................................................................
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3
Calculerle
diamètr edelatige
danslecasoul’angleunitairedetorsion nedoitpasdépasserlavaleurde
0,1degr é
par
mètr e
.
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700
L
A
T
ORSION
S
IMPLE
4
E
S
CIENCES
T
ECHNIQUES
C
OURS
G
ENIE
M
ECANIQUE
(1213) Page5/8 F
LEXIO N
P
LANE
S
IMPLE
LaboratoireMécaniquedeKORBA http://mimfs.jimdo.com/ ProposéparM
r
BenAbdallahMarouan
III.2Ar br eInter médiair e:
Un
ar brepleindedia mètr ed
etdelongueur
L
égaleà
2m
transmetune
puissance
de
20kw
àla
vitesse
de
1500tr /mn
entreun
récepteuretunmoteur.L’arbrereposesurdeux
paliersA
et
B
.
Larésistancepratiqueauglissementdumatériaudel’arbreestde
R
pg
=8daN/mm²
.
1
Calculerlecoupledetorsionagissant surl’arbre(
Mt
)
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..........................................................................................................
2
Déterminerle
diamètr emini
del’arbreetcalculerl
angledetorsion
entreAetBsachantque
G=8000da N/mm².
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3
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Recepteur
L=2000
MoteurA
d
B
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