Examen 2016 - Université de Rennes 1

a
a a
a
n m = 2n −1
n2m
n2m
p q n =pq m
n
c=m2n
cp+1
4=√c p
n

R
n x < n x n
c=x2n m =R(c)p q m x
n
n
172107
F∗
107
F∗
107 758107
ρ