Fiche d`exercices No. 3

EAEB
mA−mB
L
T R
L= 4πR2σT 4,
σ= 5.67 ×10−8−2−4
M T R TRM
−26.7
d= 1.32
d= 8
dM= 0.524
mP= 11.3mD= 12.4
αM
RM= 3400
RP= 11.1RD= 6.2αPαD

E
LE
d
d= 1.32 L= 3.86 ×1026
m= 6
m=−2.5 log E
E0
E0= 2.87 ×10−8−2
E
P D
E P
D
m(D) = m0+ 5 log D D m0
m D = 6 D= 60 D= 6
M
n
d
N(d)d
m N(m) = α10βm α β
α