ISCID-CO - Prépa 1 ULCO MATHÉMATIQUES

5x3−x
2
3xy −4yz + 2xz
52x3−19y5
3
x−5
5x3−8x+ 3x5+ 4x2−7x4+ 1
f(x)g(x)
f(x) + g(x)
f(x)×g(x)
f(x)−g(x)
f(x)
g(x)
3x4+ 4x3+ 3x2−3xy −5
3x3−4x3−3x
3x4−4x3−3xy
3x2−3xy −5
2x2+ 4x−30 2[(x+ 1)2−16] 2(x−3)(x+ 5)
f
f(0) f(3) f(−5) f(−1) f(−2)
x2+ 4x+ 5 (x+ 2)2+ 1
g
g(x)x
g
f(x) = 2x3+ 4x2−5x+ 7
g(x) = (−x+ 7)4
h(x) = (2x2+ 5x−7)9

y2+ 3y
4xy −xy2+ 27x2y
−6x2+ 12x−6
9xy −27xy3+ 54x2y
25x2−y2
36y4−6x2
x= 1 x= 2 x=3
4
x=−1x= 3 x= 0
f(x) = x2+x−2f(−2) = 0
f(x) = x3+x2−3x−3f(√3) = 0 f(−√3) = 0
fRf(x) = x2−x−2
f′(x)f f
ACff
Cf−2
Cf
CfA
2−4
−16
16
1
16
−1
16
1−16
(√2)10/3
25
210
(√2)10/9
3(√2)10/3
2x+x2x=−2
−15
4
17
4

3x2+ 3x4+ 4(−1) +xy
0
1
0
3x2y6+ 4xy8+ 2x4y5
4xy + 2x2y+ 3xy−4
y
f f(x) = 4x−1
x+2 C
f−∞ +∞ −2
Cf′(x)f
x f′(x) = 1
C C x f′(x) = 1
P
P(0) = 1 P(1) = 0 P(−1) = −2P(2) = 4
P(x) = x5+ 6x4+ 10x3−20x2−51x−26
−1 2 P
PR

= ∆Y/∆X
y′
x2−2x+ 1 >0
−3x2+ 5x−260
x(2x−5) >x−6
e3x2+4x+5
(x+ 3)(x−1)(x+ 2)2
x2−x+ 1
x2−3x+ 3
m4x2+ (m−1)x+ 1 = 0
m
3,−2,4
2−3 4
−1 4
1,−1,3,−2 2

y=x2+ 1
x=−2
y′
x=−2
= ∆Y/∆X
f(x) = −5+3x−2x3
f(x) = √5x2+ 3x−4
f(x) = x2+ 3x+ 5
2x+ 5
f(x) = e2x2−4x+6
f(x) = (5x−6)4(3x+ 8)
f(x) = 4x2+ 2
f(x) = 3x3−2x+√x
f(x) = 12 −4x5+ 3x2
f(x) = ex+ 1
λ
P(x) = x3−3x+λ
P(x) = 0