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FACHZEITSCHRIFT ET ELEKTROTECHNIK  AUSGABE FEBRUAR 2016
Seite 1 von 7
BAWI ELEKTROBERUFE GMBH  MATHEMATIK
13.01.2016  Pascal Canova
Mathématique
Solution Exercice 1
 58
 46
 57
 52
 47
 50
Solution Exercice 2
 322m 2dm 2cm  6dm 1cm 2mm  5dm 5cm  12km 5m
 16kg 850g  7t 600kg  15g  2g 755mg
 1km2 67ha 90a  4ha 88a  93a 64m2 50dm2  12dm2 33cm2
 8m3 721dm3  991cm3 200mm3  48 5d  6h 60 5d
 77dm 2cm 2mm  5cm 5mm  9m 3dm 2cm  100m 8dm
 67cm2 50mm2  15km2 82ha 5a  33a 70m2  2a 25m2
Solution Exercice 3
U
I=R
21
Q
=+
m• c
E
2L 1
U
R = -R
I
r0
C•
ε= •A
P
I=U• 3 •cos
U• A
=• 2•I•cos

FACHZEITSCHRIFT ET ELEKTROTECHNIK  AUSGABE FEBRUAR 2016
Seite 2 von 7
BAWI ELEKTROBERUFE GMBH  MATHEMATIK
13.01.2016  Pascal Canova
Solution Exercice 4
Part entreprise B = x / Part entreprise A = 0.5x / Part entreprise C = 0.65x / Part entreprise D = 0.13x
x + 0.5x + 0.65x + 0.13x = 11‘400.-
2.28x = 11‘400.-
x = 5‘000.-
Part entreprise B = CHF 5‘000.-
Part entreprise A = 0.5x  CHF 5‘000.- = CHF 2‘500.-
Part entreprise C = 0.65x  CHF 5‘000.- = CHF 3‘250.-
Part entreprise D = 0.13x  CHF 5‘000.- = CHF 650.-
Solution Exercice 5
Hypoténuse du triangle rectangle
=
22
1'100mm-500mm + 600mm =848.5mm
 Périmètre U = 1‘100mm + 600mm + 500mm + 848.5mm = 3‘048.5mm = 304.85cm
 Aire partie 1 = 50cm  60cm = 3‘000cm2 Aire partie 2 = 0.5(60cm  60cm) = 1‘800cm2
Aire A totale = 3‘000cm2 + 1‘800cm2 = 4‘800cm2 = 48dm2
Solution Exercice 6
 0.075  0.08
 0.7  0.625
 0.02  0.27
 0.28  0.4
 0.1  0.9
 0.7  0.05
Solution Exercice 7
900.-•100%
Rendite = =
15'000.- 6%
Rendite = Rendement
Solution Exercice 8
Volume: V = 6cm  200cm  1cm = 1‘200cm3 = 1.2dm3
Poids: m = V   = 1.2dm3  8.9kg/dm3 = 10.68kg
Solution Exercice 9
Répartition d’après la longueur des côtés
Caractéristique
Les trois côtés ont des
longueurs différentes
Tous les trois côtés sont
égaux
Deux côtés sont égaux
Désignation
Triangle quelconque
Triangle équilatéral
Triangle équilatéral
Triangle
A
C
B
a
c
b
A
C
B
a
c = a
b = a
A
C
B
a
c
b = a

FACHZEITSCHRIFT ET ELEKTROTECHNIK  AUSGABE FEBRUAR 2016
Seite 3 von 7
BAWI ELEKTROBERUFE GMBH  MATHEMATIK
13.01.2016  Pascal Canova
Répartition d’après les angles
Caractéristique
Tous les angles sont
aigus
Un angle est obtus
Un angle forme un angle
droit
Désignation
Triangle acutangle
Triangle obtusangle
Triangle rectangle
Triangle
A
C
B
A
B
C
A
C
B

FACHZEITSCHRIFT ET ELEKTROTECHNIK  AUSGABE FEBRUAR 2016
Seite 4 von 7
BAWI ELEKTROBERUFE GMBH  MATHEMATIK
13.01.2016  Pascal Canova
Solution Exercice 10
 2(4x – 8) + 10 = 18
8x – 16 + 10 = 18
8x – 6 = 18
8x = 24
x = 3
 5(5x – 4) = 11(2x + 5)
25x – 20 = 22x + 55
3x = 75
x = 25
 18 – 5(3 – 3x) = 9x – 3(3 – x)
18 – (15 – 15x) = 9x – (9 – 3x)
18 – 15 + 15x = 9x – 9 + 3x
3 + 15x = 12x – 9
3x = – 12
x = – 4
 2(6x – 3) = 9(2x – 6)
12x – 6 = 18x – 54
48 = 6x
8 = x
 2a – x(a + b) = x(a – b)
2a – (ax + bx) = ax – bx
2a – ax – bx = ax – bx
2a = ax – bx + ax + bx
2a = 2ax
1 = x
 (x + 2)2 – (x + 1)2 = 3(x + 3)
(x + 2) (x + 2) – (x + 1) (x + 1) = 3x + 9
x2 + 2x + 2x + 4 – (x2 + 1x + 1x + 1) = 3x + 9
x2 + 4x + 4 – x2 – 2x – 1 = 3x + 9
2x + 3 = 3x + 9
– 6 = x
Solution Exercice 11
y = b  ax → y = 7.5Mio.  1.01114 = 8.741Mio. d’habitants

FACHZEITSCHRIFT ET ELEKTROTECHNIK  AUSGABE FEBRUAR 2016
Seite 5 von 7
BAWI ELEKTROBERUFE GMBH  MATHEMATIK
13.01.2016  Pascal Canova
Solution Exercice 12 15
Volume V =
3
34• • 1dm
4• •r ==
33 3
4.189dm
Surface A0 = 4    r2 = 4    (1dm)2 = 12.566dm2
Solution Exercice 13
 (a + b) (a + b) = a2 + 2ab + b2
 (a – b) (a – b) = a2 – 2ab + b2
 (a + b) (a – b) = a2 – b2
 (a + b) (a + b) (a + b) = a3 + 3a2b + 3ab2 + b3
 (a + b) (– a + b) = – a2 + b2
 (– a – b) (– a + b) = a2 – b2
Solution Exercice 14
 12a – 24b + 16 = 4(3a – 6b + 4)
 x3y – xy2 – 5xy = xy (x2 – y – 5)
 6a3bc – 3ab2c – abc2 = abc (6a2 – 3b – c)
 – 9ab2 + 6a2b + 9b = 3b (– 3ab +2a2 + 3)
 20a2b3 + 8a3b2 – 8ab2 = 4ab2 (5ab + 2a2 – 2)
 x3 + 3x2yz – 6x2y = x2 (x + 3yz – 6y)
Solution Exercice 15
Pompe 1 → 15h = 4‘500
1h = 300
Pompe 2 → 12h = 4‘500
1h = 375
les deux pompes ensemble → 1h = 675
xh = 4‘500→ xh =
4'500
=
675 6.66h = 6h 40min.