Module EN1 - Composants de base de l`électronique Travaux Dirigés

Module EN1 - Composants de base de l’´electronique
Travaux Dirig´es
´
Eric PERONNIN

VeVpVe(t) = Ve1(t) = Ve2(t) = Veef f .√2.sin(ω.t)
Vp(t) = Vpef f .√2.sin(ω.t)
Veef f = 12v Vpef f = 240v R = 15Ω ω= 2.π.F F = 50Hz
D
RVe Vs
I
V
D
D
D1
Vp
I
Vs
V
D1
R
T1
2 6
9
7
104
D2I
V
D2
D1
D2
Ve1
Ve2
(c)
(b)(a)
Ip
D1
R
V
Ie
D4
D3
D2
Ve Vs
D1
V
V
V
D2
D3
D4
I1
I2
I3
I4
Is
VDIDVsIsVeIe
VsIs
VDID

VRM ˆ ID
< ID> IDef f
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20

0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20

0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
0 0.005 0.01 0.015 0.02
−20
−15
−10
−5
0
5
10
15
20
Vsmin
Ve(t) = Veef f .√2.sin(ω.t)
Veef f = 12v R = 15Ω ω= 2.π.F F = 50Hz
C= 47µF C = 470µF C = 4700µF
D
R
I
V
D
D
VsVe
Ic Is
C
t= 0
Ic(t)Is(t)ID(t)