2n1
211 = 1
(n1) 2(n1) 1
(n1) 2n11
2n1(n1)
2n11+2n1= 2n1
(i, j, n)∈ {1,2,3}2×N
n6= 0
T our de Hanoi(i, j0(6=i, 6=j), n 1)
deplacer(i, j)
T our de Hanoi(j0, i, n 1)
O(2n)
nN
← 6=6=
← 6=6=6=
1 / 3 100%