Thème 6 - Université du Maine

M.V =P.Y
Y=M.V
P
Y=C(Y−T) + I(r) + G
M
P=L(r, Y )

C=P MC(Y−T)
4G= 1
4C=P MC4Y=P M C4G=P MC
4Y=P MC 4C=P MC4Y=P M C ×P MC
4Y= (1 + P MC +P M C2+P M C3+....)4G
4Y
4G=1 1−P MC

C= 0.75Yd+ 500
T= 0.2Y+To
I=−1000r+ 100
Md=P[0.4Y−2000r]
Yd
To
MdMs
To
M
P
To
To
Y=C+I+G
Y= 0.75[Y−0.2Y−To] + 500 −1000r+ 100 + G

Y=−15
8To−2500r+ 1500 + 5 2G
Y= 3375 −2500r
Ms
Ms
Ms=Md
Ms=P[0.4Y−2000r]
Y=5Ms
2P+ 5000r
Y= 3000 + 5000r
ToMsMsTo
Y=−15
8To−2500r+ 1500 + 5 2G
Y=5Ms
2P+ 5000r
Y∗= 1000 + 1
6[5M P−30 4To+ 10G]
r∗= 0.2 + 1
3000[−M P−3To 4+G]
Y∗= 3250 r∗= 5%
T−G= 0.2Y∗+To−G= 0

MsTo
∂Y ∗
∂G =10 6
∂r∗
∂G =1 3000
Y∗= 3500 r∗= 10%
∂Y ∗
∂M =5 6
∂r∗
∂M =−1 3000
r∗= 0.2 + 1
3000[−M P−3To 4+G]
r∗= 0.05 G= 1200 To= 400 P= 1
5%
G= 1200 M= 1350
Y∗= 3625
T−G= 0.2Y+To−G=−75