Exemple d`étude de complexité algorithmique

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ak+1=ak+2bk
bk+1=4bk
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bk=4k
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ak=4k−1
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ck=6bi
i=0
k−1
∑=4k−1
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C(n)=ck+4bk+1=3.4k=9n−6
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ak+1=ak+ α ( α −1)bk
bk+1= α
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bk= α
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ak=
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ck=
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C(n)=ck+2 α bk+1=(2
α
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α −1)n−2( α
2−
α +1)
α −1