sm7 168

________________________________________________________________________
PROBLEM (*7.168) The allowable stress for the clamp shown in Fig. P7.168 is σall = 10 ksi.
Determine the maximum permissible load P that the member can resist.
*SOLUTION
2
8(2) 4(2) 4(2) 32 .Ai=++=n
16(11) 8(14) 8(17) 13.25 .
32
ri
n
++
==
P
Hence
12 16 18
10 12 16
32
824
A
RdA dr dr dr
rrr
==
++
∑∫∫ ∫ ∫
r
32 12.7739 .
12 16 18
8ln 2ln 4ln
10 12 16
in
==
++
0.4765 .erR in=−=
(13.25 2.5) 15.75
M
PP=− + =−
Apply Eq.(7.70);
3
() 15.75(12.7739 10)
]; 10(10 ) 1 , 31.47
32 (0.4765)(10)
A
AA
MR r
PP Pk
AAer
σ
⎡⎤
−−
=− = + =
⎢⎥
⎣⎦
ips
3
() 15.75(12.7739 18)
]; 10(10 ) 1 , 37.22
32 (0.4765)(18)
B
BB
MR r
PP Pk
AAer
σ
⎡⎤
−−
=− − = + =
⎢⎥
⎣⎦
ips
ips
So
31.47
all
Pk=
A
M
P
B
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