________________________________________________________________________
PROBLEM (*7.81) Given that all
σ
= 9 MPa and all
τ
= l.l MPa, design the cross section of
a rectangular wooden beam loaded as shown in Fig. P7.81.
Assumption: The beam is to be twice as deep as it is wide (h = 2b).
*SOLUTION
kNRRM DDC 5.420)4()2(8015)5.2(2:0 ==+=
kNRF Cy 5.39:0 ==
From geometry:
4, 1.875
37.5 42.5
mm
m
xx
x
m
==
max 1(42.5)(4 1.875) 45.156
2
M
kN m=−= ⋅
Thus,
max
23
3
62
all M
M
bh b
σ
==
3
63
3
3 45.156 10
9 10 , 196 10
2bm
b
×
×= =×
3
2
all V
A
τ
=
3
63
2
3 42.5 10
1.1 10 , 170 10
22 bm
b
×
×= =×
The required dimensions are
mmhmmb 392196
=
=
-3
20 kN/m
1.5 m
A
B
x
V, kN
42.5 kN
4 m 2b
1
m
C
D
12
-4.8
39.5 kN
37.5
8
x
15 kN m
b
,
kN m
x
m-42.5
2 kN
max
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