________________________________________________________________________
PROBLEM (7.54) Redo Prob. 7.53, given that the cross section of the beam is turned 90°.
SOLUTION
y
C
y
z
A
1
15
z
100
25
C
2020
100
25
40
Dimensions are
in millim
e
t
e
r
s
(b)
(a)
33 6
1[140(100) 100(50) ] 10.67 10
12 4
I
mm=−=×
(a) Refer to Fig. (a): 33
111 1075.935.3725100 mmyAQ ×=××==
36
6
3 10 (93.75 10 ) 26.36
10.67 10
VQ
qk
I
−
−
××
== =
×Nm
3
11
(26.36 10 )(0.1) 1.32
22
Fqs k== × = N
(b) Refer to Fig. (b):
33
1075.141)5.172015(25.3725140 mmQ ×=××+××=
36
63
3 10 (141.75 10 ) 996
10.67 10 (2 20 10 )
VQ kPa
Ib
τ
−
−−
××
== =
×××
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