________________________________________________________________________ PROBLEM (11.76) Calculate the allowable axial load P for a 100-mm by 200-mm rectangular timber column if the effective length is: (a) L e = 2 m. (b) L e = 4 m. Given: E = 11 GPa, σall = 9 MPa SOLUTION A = 100 × 200 = 20 × 103 mm 2 , (a) Le = 2 m d = 100 mm Le d = 20 Equation (11.32) : 0.3(11× 109 ) σ all = = 8.25 MPa < 9 MPa (20) 2 Hence, Pall = 8.25 ×106 (20 × 10−3 ) = 165 kN (b) Le = 4 m Le d = 40 Equation (11.32) : 0.3(11×109 ) σ all = = 2.06 MPa < 9MPa (40) 2 And Pall = 2.06 × 106 (20 ×10−3 ) = 41.2 kN Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States Copyright Act without the permission of the copyright owner is unlawful.