________________________________________________________________________
PROBLEM (11.81) Redo Prob. 11.80 for the case in which the column is made of steel.
Given: (σall )b = 160 MPa σy = 250 MPa E = 200 GPa
SOLUTION
From solution of Prob. 11.80 :
64
8.333 10 50
I
mm c mm=× = ,
42
110 0.04AmmM=× = P
Therefore,
6
2
8.333 10 28.9
110
rm
m
−
−
×
==
×, 3
4 10 28.9 138.4
e
Lr=× =
29
6
2 (200 10 ) 125.7
250 10
c
C
π
×
==
×
Thus,
ec
C>Lr and we use Eq. (11.25) :
229
53.67
22
(200 10 )
()1.92( ) 1.92(138.4)
all c e
E
Lr
ππ
σ
×
==
M
Pa
=
Then
1
()()
all c all
PA McI
σσ
+≤
Becomes
26
66
1 10 0.04 (0.05) 8.333 10 1
53.67 10 160 10
PP
−−
××
+≤
××
, 297PkN
≤
Therefore
max 297Pk=N
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