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PROBLEM (11.75) Determine the allowable axial load P for a built-up timber column of the cross
section shown in Fig. P13.75. The effective length is Le = 15 ft.
Given: E = 1.6 x 10 6 psi, σall = 2 ksi
SOLUTION
Le = 15 ×12 = 180 in. ,
A = 102 − 7 2 = 51 in.2
Use Eq. (11.32) :
0.3(1.6 × 106 )
σ all =
= 1.48 ksi < 2 ksi
(18) 2
Thus,
Pall = 1.48(51) = 75.5 kips
d = 10 in.2
Le d = 18
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