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sm11 35

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PROBLEM (*11.35) A 60-in. long, 2 in.-diameter round column is fixed at its base and
pinned at its top. Calculate the axial buckling load P cr , if the stress-strain diagram for the material
is approximated as depicted in Fig. P11.35.
*SOLUTION
A=
πd2
4
I=
πd4
64
r=
Le = 0.7 L = 0.7(60) = 42 in.
I d 2
= = = 0.5 in.
A 4 4
(see Fig. 11.3c),
Le 42
=
= 84
r 0.5
Equation (11.12):
π 2 Et
π 2 Et
=
= 141.7(10−6 ) Et
(1)
σ cr =
2
2
( Le r )
(84)
From stress-strain diagram, we have
15 ×103
(45 − 15)103
Et = E =
= 15 × 106 psi
Et =
= 5 × 106 psi
0.001
0.007 − 0.001
Equation (1) gives
σ cr = 141.7(10−6 )(15 ×106 ) = 2.13 ksi < 15 ksi (O.K.)
σ cr = 141.7(10−6 )(5 × 106 ) = 0.709 ksi < 15 ksi
(not valid)
Thus
Pcr = σ cr A = 2.13[π (1) 2 ] = 6.69 kips
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