________________________________________________________________________
PROBLEM (11.49) Resolve Prob. 11.48, assuming that ends B and A of column AB are
fixed and free, respectively.
SOLUTION
Refer to solution of Prob. 11.48 21.4
e
LL== .m
22 9 9
126.6 kN
22
(200 10 )(125.66 10 )
(1.4)
cr e
EI
PL
ππ
−
××
==
=
(a) Equation (11.18):
360
0.6 10 sec 1 [sec(62 ) 1]
2 126.6 o
ee
π
−⎡⎤
⎛⎞
×= −= −
⎢⎥
⎜⎟
⎜⎟
⎢⎥
⎝⎠
⎣⎦
, 0.53emm
=
(b) max
( ) 60(0.6 0.53) 67.8
M
Pv e N m=+=+= ⋅. Therefore,
max PMc
AI
σ
=+
3
9
67.8(20 10 )
47.75 125.66 10
−
−
×
=+ ×47.75 10.8 58.6
M
Pa
=
+=
Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or
instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other
reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States
Copyright Act without the permission of the copyright owner is unlawful.
1
/
1
100%