sm11 47

________________________________________________________________________
PROBLEM (11.47) Rework Prob. 11.45 for tube with fixed-pinned ends and a factor of
safety of ns = 1.5.
SOLUTION
Refer to Solution of Prob. 11.45. We now have
(See Fig. 11.3c) 0.7 0.7(2.5) 1.75
e
LL== =m
3
1.75 10 75.92 37.94
23.05 2
ee
LL
rr
×
== =
(a) Equation (1) becomes
3
max 3
10 10
(9.794) 1 (2.141)sec 37.96 (1021)(210 10 )
σ
⎡⎤
⎛⎞
×
⎢⎥
=+ ⎜⎟
⎜⎟
×
⎢⎥
⎝⎠
⎣⎦
31.5
M
Pa=
(b) Equation (2) Leads to
616 3
250(10 ) 1 (2.141)sec 37.96
1021(10 ) (1021)(210 10 )
yy
PP
−
⎡
⎤
⎛⎞
⎢
⎥
=+
⎜⎟
⎜⎟
×
⎢
⎥
⎝⎠
⎣
⎦
Solving numerically, P Equation (11.22) results in 68.1 .
ykN=
68.1 45.4
1.5
y
all s
P
Pk
n
== = N
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