________________________________________________________________________ PROBLEMS (11.5 and 11.6) A rigid bar-spring assembly is shown in Figs. P11.5 and P11.6, where k t represents the torsional spring constant. What is the critical load P cr for the system? SOLUTION (11.5) P P RC A A θ a a aθ B B M = 2θ kt a System ABC ∑ M C = 0 : RC = 0 Bar AB ∑MB = 0: 2θ kt − Paθ = 0 , Pcr = 2 θ kt a C SOLUTION (11.6) Pcr FA Bars AC and CB We have M B = ktθ A θ M B = 0 : ktθ − 2 LFA = 0, C θ B FB FA = ktθ 2L Bar AC: M C = 0 : Pcr ( Lθ ) − LFA = 0 or k F Pcr = A = t θ 2L MB=ktθ Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States Copyright Act without the permission of the copyright owner is unlawful.