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PROBLEMS (11.5 and 11.6) A rigid bar-spring assembly is shown in Figs. P11.5 and
P11.6, where k t represents the torsional spring constant. What is the critical load P cr for the
system?
SOLUTION (11.5)
P
P
RC
A
A
θ
a
a
aθ
B
B
M = 2θ kt
a
System ABC
∑ M C = 0 : RC = 0
Bar AB
∑MB = 0:
2θ kt − Paθ = 0 , Pcr = 2
θ
kt
a
C
SOLUTION (11.6)
Pcr
FA
Bars AC and CB
We have M B = ktθ
A
θ
M B = 0 : ktθ − 2 LFA = 0,
C
θ
B
FB
FA =
ktθ
2L
Bar AC:
M C = 0 : Pcr ( Lθ ) − LFA = 0
or
k
F
Pcr = A = t
θ 2L
MB=ktθ
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