sm9 48

_______________________________________________________________________
PROBLEM (9.48) A link with a T cross section is loaded as shown in Fig. P9.48.
Determine at section A-B
(a) The maximum stress.
(b) The location of the neutral axis.
SOLUTION
y
z
10
70
20
y
M
60
y
C
20 mm
P
=48
47
A
yo
B
P
A
B
70 20(45) 60 10(5) 33
70 20 60 10
y
mm
×+×
==
×+×
mmyy 5320
0=+=
33
10210607020 mmA ×=×+×=
33
22
20(70) 60(10)
20 70(12) 60 10(28)
12 12
I=+×++×
)47.0005.0202.0572.0(106+++=
46
10249.1 mm×=
mkNM
⋅
=×= 544.2053.048
(a) 3
3
48 10 24
210
aP
M
Pa
A
σ
−
×
== =
×
6
2544(0.047)
( ) 95.7
1.249 10
bB Mc
M
Pa
I
σ
−
−
== =−
×
33
( ) 95.7 67.2
47
bA
M
Pa σ ==
MPa
A2.6724 +=
σ
MPa
A2.912.6724 =+=
σ
MPa
B7.717.9524 −=−=
σ
Continued on next slide
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(b) Apply Eq.(9.13):
66
2544
02410
1.249 10
nn
M
yy
P
AI
−
=− =× − ×
mmmyn8.110118.0 ==
A
B
x
y
n
σ
b
N
.A
σ
Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or
instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other
reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States
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