_______________________________________________________________________ PROBLEM (9.14) Calculate the normal and shearing stresses on the spiral weld of the steel shaft of diameter d acted upon by an axial load P and a torque T as shown in Fig. P9.14. Given: P = 200 kN, T = 2 kN ⋅ m, d = 50 mm, φ = 60° SOLUTION θ = α + 90 = 60 + 90 = 150 o x' P σx = A x θ τ xy = y' σx = 200 × 103 π = 102 MPa 2 (0.05) 4 16(2 × 10−3 ) τ= = 81.5 MPa π (0.05)3 16T πd3 Equations(8.4): σ w = σ x' = 102 102 cos 300o + 81.5cos 300o = 147.1 MPa + 2 2 and τ w = τ x' y' = − 102 sin 300o − 81.5cos 300o = 44.2 − 40.75 = 3.45 MPa 2 x’ 150 o 147.1 MPa x 3.45 MPa y’ Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States Copyright Act without the permission of the copyright owner is unlawful.