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PROBLEM (9.82) Referring to Fig. P9.77, design a solid steel shaft ( y
τ
= 60 MPa) subjected
to loads of R = 600 N, Q = 200 N, and P = 0. Apply the maximum shear stres theory using a
factor of safety
s
n= 1.2.
SOLUTION
At the fixed end:
200 2 400
y
M
Nm= ⋅
600 2 1.2
z
M
kN m=− × =−
600 1.5 900TNm= ⋅
A load-diagram is shown in Fig. S9.82a.
From the moment and torque diagrams we observe that the critical point
is just to the right of A.
Thus,
222 2 2 2
400 1200 900
yz
MMT++= + +
1552 Nm=⋅
Since
60 50
1.2
all
M
Pa
σ
==
Equation (9.30) is thus
3
36
16(1552) 54.1 10
(50 10 )
d
π
==×
×54.1 mm
=
Use a
55-mm diameter shaft.
x
y
A
Q
B
y
x
x
z
900 N
m
400 Nm
z
-1.2 kNm
R
2 m
T
y
T
z
T
x
Figure S9.82
d
1 / 1 100%
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