_______________________________________________________________________ PROBLEM (9.4) Determine the largest value of the axial load P that can be carried by the stepped steel shaft shown in Fig. P9.4 for allowable bending and shear shear stresses Given: σ all τ all = 60 = 100 MPa , σ all and τ all , respectively. T = 0.01P N ⋅ m. MPa, SOLUTION ACD = J CD = J AB = π 4 (582 − 502 ) = 216π mm 2 π (584 − 504 ) = 0.158π × 106 mm 4 32 π (504 ) = 0.195π × 106 mm 4 32 Since J AB > J CD , the critical section is in CD. Thus, σx = σx = τ= TcCD J CD P ACD τ =− =− P 4630 P = −6 π 216π × 10 0.01P(29 × 10−3 ) 0.158π × 10−6 1835P π Equation (9.1): 4630 P 4630 P 2 −1835 P 2 ) σ1 = + ( ) +( π 2π 2π 2315P 2954 P 5269 P = + = π τ max = π π 2954 P π We have 100 × 106 = 60 × 106 = 5269 P π 2954 P π , , P = 59.6 kN P = 63.8 kN Thus, Pall = 59.6 kN Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States Copyright Act without the permission of the copyright owner is unlawful.