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PROBLEM (*9.86) Repeat Prob. 9.85 for the case in which tensions T1 and T2 on pulley D are
in the horizontal (z) direction.
*SOLUTION
Now Fig. S9.85a (see: Solution on of Prob. 9.85) becomes as shown below. From
statics:
5.3 1.06
yy
AkNB kN==
1.05 6.01
zz
AkNBkN=− =
The moment and torque diagrams are shown in Figs. S9.86b, c, and d.
Point C:
222 2 2 2
1.06 0.21 0.636 1.254
yz
M
MT kNm++= + + = ⋅
Point D:
222
0.636 0.63 1.06 1.387 kN m++= ⋅
Point E:
22 2
0.212 1.2 1.06 1.615 kN m++ = ⋅
The critical point is therefore just to the left of E. Applying Eq. (9.30):
33
36
16(1.615)10 57 10 57
(45 10 )
dmmm
π
−
==×=
×
Use a
60 mm− diameter shaft.
x
y
A
C
B
M
y, kN⋅m
x
x
M
z , kN⋅m
z
D
0.4 m
B
z
A
z
T, kN⋅m
x
Figure S9.86
636 N⋅m
(d)
(
a
)
5.64 kN
E
10.6 kN
1060 N
⋅
m
A
y
0.63
6.36 kN
0.2 m
-1.20
B
y
424 N
⋅
m
0.636 0.212
(c)
1.06
1.06
(
b
)
0.21
0.636
1
/
1
100%