_______________________________________________________________________
PROBLEM (9.23) Determine the maximum normal stress and the maximum shear stress at a point A
of the aluminum bar of diameter d loaded as shown in Fig. P9.23.
Given: a = 5 ft, d = 2 in., R = 40 lb, P = 20 kips, T = 6 kip
⋅
in.
SOLUTION
3
23
4(20 10 ) 32(5 12 40)
(2) (2)
x
σππ
××
=+
×
3
16Td
τ
π
=
A
23
432
xPM
dd
σ
π
π
=+
ksi43.906.337.6 =+=
3
3
16(6 10 ) 3.82
(2) ksi
τπ
−×
==−
Equation (9.1):
22
19.43 9.43
( ) ( 3.82) 4.715 6.068
22
σ
=+ +− = + ksi78.10
=
ksi068.6
max =
τ
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