sm9 27

_______________________________________________________________________
PROBLEM (9.27) Redo Prob. 9.26 for a D = 40 mm shaft made of solid steel and subjected to a zero
axial load.
SOLUTION
M
M
T T
A
3
32(200) 31.83
(0.04)
x
M
Pa σπ ==
3
16(500) 39.8
(0.04)
M
Pa τπ
−
==−
3
MPa92.15'
=
σ
22
(15.92) (39.8) 42.87R=+=
MPa8.5887.4292.15
1=+=
σ
MPa2787.4292.15
2−=−=
σ
39.8
tan2 ' , ' 34.1
15.92 o
pp
θθ ==
A
3
4.1
ο
58.8 MPa
27 MPa
16T
τ
d
π
=
3
32
x
M
A
d
σ
π
=
τ
(MPa)
(
31.83, 39.8
)
2
σ
σ
(MPa)
2θp’
C
1
σ
R
'
σ
Ο
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