________________________________________________________________________ PROBLEM (10.133) The 12-ft overhanging beam AC seen in Fig. P10.125 supports a moment of M0 = -500 kip ⋅ in. Compute the maximum value of EI vmax between supports A and B. SOLUTION See solution of Prob.10.125: M/EI M0x/2aEI M0/EI A A 2a x B y C x x tA/D A θA = − vma B M 0a 3EI θD / A = θD0 − θ A = A = (1) 1 M0 2 x 2 2aEI (2) Equations (1) and (2) give 2 x= a 3 Then, M x3 2x 4 M 0a2 t A / D = A( ) = − 0 = − 3 6aEI 9 3 EI Hence, 4 M 0a2 vmax = v A / D = ↓ 9 3 EI and 4 [500 ×103 (4 × 12)2 ] = 295.6 × 106 lb ⋅ in.3 EIvmax = 9 3 Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States Copyright Act without the permission of the copyright owner is unlawful.