Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or
instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other
reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States
Copyright Act without the permission of the copyright owner is unlawful.
________________________________________________________________________
PROBLEM (10.133) The 12-ft overhanging beam AC seen in Fig. P10.125 supports a moment
of M0 = -500 kip⋅in. Compute the maximum value of EI max
v between supports A and B.
SOLUTION
See solution of Prob.10.125:
0
3
A
a
EI
θ
=− (1)
02
0
/1
22
DA D A M
Ax
aEI
θθθ
=−== (2)
Equations (1) and (2) give
2
3
a=
Then,
32
00
/24
()
36 93
AD
xMa
x
tA aEI EI
==−=−
Hence,
2
0
max / 4
93
AD Ma
vv EI
== ↓
and
32
max 4[500 10 (4 12) ]
93
EIv =×× 63
295.6 10 .lb in
×⋅
t
/D
M/EI
m
v
2a
0/EI
0x/2aEI
y