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Segment AC
111
'''' 0 '''EIv EIv C==
112
''EIv C x C=+
2
1123
1
'2
EIv C x C x C=++ (1)
32
11 234
11
62
EIv C x C x C x C=+++ (2)
Boundary conditions:
11
'''(0) :
A
EIv V wa C wa=− = =
22
12
33
''(0) :
22
EIv wa C wa=− =−
13 14
'(0) 0: 0, (0) 0, 0EIv C EIv C== ==
Segment BC
225
'''' '''EIv w EIv wx C=− =− +
2
256
1
'' 2
EIv wx C x C=− + +
32
2567
11
'62
EIv wx C x C x C=− + + + (3)
432
25678
111
24 6 2
EIv wx C x C x C x C=− + + + + (4)
Continuity conditions:
12 1 55
'''( ) '''( ) : , 2va va C waC C wa==−+=
22
22
12 66
''( ) ''( ) : 2 , 2
22
wa wa
v a v a wa C C wa=−=−++ =−
3
333 3
22 77
1
'( ) '( ) : 2 ,
66
wa
v a v a wa wa wa C C wa=−=−+−+ =
12
444
44
88
() ():
71
,
12 24 3 6 24
va va
wa wa wa
wa C C wa
=
− =−+++ =−
Then, Eqs.(1) through (4) yield the results given in solution of Prob.10.4.