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sm10 159 160

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PROBLEMS (10.159 and *10.160) A two-span continuous beam ABC is loaded as shown in
Figs. P10.159 and P10.160. Find the reactions RA , RB , and RC for the beam.
SOLUTION (10.159)
Consider RB as redundant.
P
-tC/B= tA/B
P
B
A
RA
2EI
a
C
a
2a
tangent at B
RB
M
EI
tC/B
RC
a
A1
A
A1
-Pa/2
M
C
x
4a/3
B
A
A2
A2
C
1 Pa
1
(2a) = Pa 2
2 2
2
1
A2 = M B (2a) = M B a
2
2
2 EIt A / B = − A1 (a) − A2 ( ⋅ 2a)
3
2
EIt B / C = − A1 (a) − A2 ( ⋅ 2a )
3
A1 =
x
-MB
We have
t A / B = − tC / B : −
from which
Pa 3 2
Pa 3 4M B a 2
− M B a 2 = −(
−
)
4
3
2
3
1
M B = Pa
8
Segment BC:
M B = RC (2a) − Pa
Continued on next slide
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Thus,
Pa
= RC (2a ) − Pa ,
8
Segment AB:
Pa
−
= − RA (2a ) + Pa ,
8
1
Statics:
RB = P ↑
8
−
RC =
7
P↑
16
RA =
9
P↓
16
w
tC/B
A
tA/B
M
L
tangent at B
RA
B L/2
C
RC
RB
L/2
wL2/8
A1
L/3
A2
2L/3
A3
x
-RCL/2
Continued on next slide
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instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other
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SOLUTION (*10.160)
Assume RC as redundant.
2 wL2
wL3
( L) =
3 8
12
R L2
1 RC L
( L) = − C
A2 = −
2 2
4
RC L2
1 RC L L
( )=−
A3 = −
2 2 2
8
A1 =
2L
L
wL4 RC L3
EIt A / B = A1 ( ) − A2 ( ) =
−
2
3
24
6
3
R L
L
EItC / B = A3 ( ) = − C
3
24
We have
R L3 wL4 RC L3
2tC / B = −t A / B : C =
−
,
12
24
6
Statics:
3
5
RB = wL ↑
RA = wL ↑
4
12
RC =
1
wL ↓
6
Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or
instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other
reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States
Copyright Act without the permission of the copyright owner is unlawful.
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