________________________________________________________________________ PROBLEM (*12.7) A solid tapered bar AB of length L is fixed at one end and subjected to .force P at the other end (Fig. Pl 2.7). Verify that the strain energy of the bar is U = P2 L π Ed 2 (P12.7) where d is the diameter at the free end. *SOLUTION dx x ρ d 2d A ρ= d 2 x L O P B L L dV = Adx = πρ 2 dx or π d 2 x2 d 2 2 dV = π ( x) dx = dx 4 L2 L Thus, σ= P P 4 L2 P = = A (π dx 2 4 L2 ) π d 2 x 2 We have U0 = σ2 2E = 8 L4 P 2 π 2d 4 x4 E U = ∫ U 0 dV = C ∫ V 2L L Let dx 1 =C − 2 x x ⎡ 1 1⎤ P L = C ⎢− + = 2 ⎣ 2 L L ⎥⎦ π Ed C= 2P 2 L2 πd2 2L L 2 Q.E.D Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States Copyright Act without the permission of the copyright owner is unlawful.