_______________________________________________________________________
PROBLEM (8.111) Using Mohr's circle, redo Prob. 8.106.
SOLUTION
400 800
' 200
2
ε
μ
+
==
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17.5
tan 51.34
6o
α
==
34.5160180
=
β
o
66.68=
22
600 750 960.5R
μ
=+=
o
x66.68cos5.960200
'+=
ε
μ
550350200
=
+
=
μ
ε
150350200
'
=
=
y
)22.68sin5.960(2
'' o
yx =
γ
μ
1789
=
O
γ
(μ)
220
(
μ
)
C
0
400, -750)
α
y’
(-
60o
x’
y
R
x
1 / 1 100%
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