sm8 53

_______________________________________________________________________
PROBLEM (8.53) Using Mohr's circle, solve Prob. 8.5.
SOLUTION
10 MPa
O
τ (MPa)
σ
(MPa)
C
40 MPa
(-40, -10)
α
22.5o
x
’
x
σ
’=15
R
y’
55.3o
(70,
1
0)
(
σx’, σ y’)
70 MPa
110
tan 10.3
55 o
α
−
==
x
’10 MPa
y
’16.8 MPa 46 MPa
22.5o
40 MPa
x
70 MPa
1
2
22
(10 55 ) 55.9R=+ =
MPa
o
yx 463.55sin9.55
'' ==
τ
153.55cos9.55
'+−= o
x
σ
MPa8.16−=
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