sm8 65

_______________________________________________________________________
PROBLEM (8.65) Using Mohr's circle, solve Prob. 8.29.
SOLUTION
65 30 25
xyxy
M
Pa MPa MPa
σ
στ ===
(a) 1(65 30)
2
47.5
avg
M
Pa
σ =+
=
25
tan , 55
17.5 o
αα ==
22
17.5 25
30.5
R
M
Pa
=+
=
1,2 47.5 30.5
σ
=
±
or
178
M
Pa
σ
=
17.5
x
B
1
A
1
C
25
σ
(MPa)
τ (MPa)
O
R
65
47.5
A
y
α
217
M
Pa
σ
=
(b) max 30.5
R
MPa
τ
==
Sketch of results is shown in solution of Prob. 8.29.
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