_______________________________________________________________________
PROBLEM (8.73) Using Mohr's circle, solve Prob. 8.47.
SOLUTION
22
max 10 20 22.4R
τ
== + =
50 30
'4
20
M
Pa
σ
+
=− =−
120
2tan
10
p
θ
=o
4.63=
31.7o
p
θ
=
140 22.4 17.6
M
Pa
σ
=− + =−
240 22.4 62.4
M
Pa
σ
=− − =−
Sketches of results are as shown in solution of Prob. 8.47.
τ (MPa)
(−50, 20
)
O
2p
θ
10
20
σ2
1
σ
R
C
MPa)
40
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